INFORMIX-ESQL/C Programmer's Manual ESQL/C Function Library

The ifx_int8toasc() function converts an int8 type number to a C char type value.

mint inf_int8toasc(int8_val,  strng_val,  len)

	ifx_int8_t  *int8_val;

	char    *strng_val;

	mint    len;

 



int8_val

is a pointer to the int8 structure whose value ifx_int8toasc() converts to a text string. 


strng_val  

is a pointer to the first byte of the character buffer where the ifx_int8toasc() function places the text string. 


len

is the size of strng_val, in bytes, minus 1 for the null terminator. 

If the int8 number does not fit into a character string of length len, ifx_int8toasc() converts the number to an exponential notation. If the number still does not fit, ifx_int8toasc() fills the string with asterisks. If the number is shorter than the string, ifx_int8toasc() left-justifies the number and pads it on the right with blanks.

Because the character string that ifx_int8toasc() returns is not null terminated, your program must add a null character to the string before you print it.

When you use a nondefault locale (one other than U.S. English), ifx_int8toasc() supports non-ASCII characters in the strng_val character string. For more information, see the Informix Guide to GLS Functionality.

The file int8toasc.ec in the demo directory contains the following sample program.

/*

* ifx_int8toasc.ec *

The following program converts three string

constants to INT8 types and then uses ifx_int8toasc()

to convert the INT8 values to C char type values.

*/

#include <stdio.h>

#define END sizeof(result)

EXEC SQL include "int8.h";

char string1[] = "-12,555,444,333,786,456";

char string2[] = "480";

char string3[] = "5.2";

char result[40];

main()

{

mint x;

ifx_int8_t num1, num2, num3;

printf("IFX_INT8TOASC Sample ESQL Program running.\n\n");

if (x = ifx_int8cvasc(string1, strlen(string1), &num1))

{

printf("Error %d in converting string1 to INT8\n", x);

exit(1);

}

if (x = ifx_int8cvasc(string2, strlen(string2), &num2))

{

printf("Error %d in converting string2 to INT8\n", x);

exit(1);

}

if (x = ifx_int8cvasc(string3, strlen(string3), &num3))

{

printf("Error %d in converting string3 to INT8\n", x);

exit(1);

}

printf("\nConverting INT8 back to ASCII\n");

printf(" Executing: ifx_int8toasc(&num1, result, END - 1)");

if (x = ifx_int8toasc(&num1, result, END - 1))

printf("\tError %d in converting INT8 to string\n", x);

else

{

result[END - 1] = '\0'; /* null terminate */

printf("\n The value of the first INT8 is = %s\n", result);

}

printf("\nConverting second INT8 back to ASCII\n");

printf(" Executing: ifx_int8toasc(&num2, result, END - 1)");

if (x= ifx_int8toasc(&num2, result, END - 1))

printf("\tError %d in converting INT8 to string\n", x);

else

{

result[END - 1] = '\0'; /* null terminate */

printf("\n The value of the 2nd INT8 is = %s\n", result);

}

printf("\nConverting third INT8 back to ASCII\n");

printf(" Executing: ifx_int8toasc(&num3, result, END - 1)");

/* note that the decimal is truncated */

if (x= ifx_int8toasc(&num3, result, END - 1))

printf("\tError %d in converting INT8 to string\n", x);

else

{

result[END - 1] = '\0'; /* null terminate */

printf("\n The value of the 3rd INT8 is = %s\n", result);

}

printf("\nIFX_INT8TOASC Sample Program over.\n\n");

exit(0);

}

IFX_INT8TOASC Sample ESQL Program running.


Converting INT8 back to ASCII
 Executing: ifx_int8toasc(&num1, result, sizeof(result)-1)
 The value of the first INT8 is = -12555444333786456

Converting second INT8 back to ASCII
 Executing: ifx_int8toasc(&num2, result, sizeof(result)-1)
 The value of the 2nd INT8 is = 480

Converting third INT8 back to ASCII
 Executing: ifx_int8toasc(&num3, result, END)
 The value of the 3rd INT8 is = 5

IFX_INT8TOASC Sample Program over.