INFORMIX-ESQL/C Programmer's Manual ESQL/C Function Library

The ifx_int8tolong() function converts an int8 type number into a C long type number.

mint ifx_int8tolong(int8_val,  lng_val)

	ifx_int8_t  *int8_val;

	int4    *lng_val;

 



int8_val  

is a pointer to an int8 structure whose value ifx_int8tolong() converts to an int4 integer type value. 


lng_val

is a pointer to an int4 integer where ifx_int8tolong() places the result of the conversion. 

The file int8tolong.ec in the demo directory contains the following sample program.

/*
* ifx_int8tolong.ec *

The following program converts three strings to INT8 types and
converts the INT8 type values to C long type values.
Then the values are displayed.

*/

#include <stdio.h>

EXEC SQL include "int8.h";

char string1[] = "-1,555,345,698";
char string2[] = "3,235,635";
char string3[] = "553.24";

main()
{
int x;
long l =0;
ifx_int8_t num1, num2, num3;

printf("IFX_INT8TOLONG Sample ESQL Program running.\n\n");

if (x = ifx_int8cvasc(string1, strlen(string1), &num1))
{
printf("Error %d in converting string1 to INT8\n", x);
exit(1);
}
if (x = ifx_int8cvasc(string2, strlen(string2), &num2))
{
printf("Error %d in converting string2 to INT8\n", x);
exit(1);
}
if (x = ifx_int8cvasc(string3, strlen(string3), &num3))
{
printf("Error %d in converting string3 to INT8\n", x);
exit(1);
}
printf("\nConverting INT8 to long\n");
if (x= ifx_int8tolong(&num1, &l))
{
printf("\tError %d in converting INT8 to long\n", x);
exit(1);
}
else
{
printf("String 1= %s\n", string1);
printf("INT8 value is = %d\n", l);
}

printf("\nConverting second INT8 to long\n");
if (x= ifx_int8tolong(&num2, &l))
{
printf("\tError %d in converting INT8 to long\n", x);
exit(1);
}
else
{
printf("String2 = %s\n", string2);
printf("INT8 value is = %d\n",l);
}
printf("\nConverting third INT8 to long\n");

/* Note that the decimal places will be truncated. */

if (x= ifx_int8tolong(&num3, &l))
{
printf("\tError %d in converting INT8 to long\n", x);
exit(1);
}
else
{
printf("String3 = %s\n", string3);
printf("INT8 value is = %d\n",l);
}
printf("\nIFX_INT8TOLONG Sample Program over.\n\n");
exit(0);
}

IFX_INT8TOLONG Sample ESQL Program running.

Converting INT8 to long

Executing: ifx_int8tolong(&num1,&l)
String 1= -1,555,345,698
The value of the first long is = -1555345698


Converting second INT8 to long

Executing: ifx_int8tolong(&num2, &l)
String2 = 3,235,635
The value of the second long is = 3235635


Converting third INT8 to long

Executing: ifx_int8tolong(&num3, &l)
String3 = 553.24
The value of the third long is = 553

IFX_INT8TOLONG Sample Program over.