In article <434h59$msg@mother.usf.edu>, smorrow@dotrisc.cfr.usf.edu (Steve Morrow) says:
>
> My problem is a last digit of
>zero. In the "grand scheme" of the EBCIDIC world, a zero translates
>to the ASCII char of 208, AKA hex D0. Thus, for a negative charge
>of -$954.00, I would supply 0009540X (where X simply represents the
>'unprintable?' char of ASCII 208 in this case).
>
Since you are using the A->I for positive and J->R for negative,
the standard for +0 is { and -0 is }. I am not sure where the
ASCII 208 comes from.
Try that.
Steve Goldberg
Landata RE-Source
steveg@landata.com