ESQL and dttofmtasc() problem

I am trying to use the dttofmtasc() in ESQL without success. I get an error message -1228 (which is undefined on my system). The only time that I can use the dttofmtasc function without getting a -1228 error is if I use a format string of "". The Esql version is: INFORMIX-ESQL Version 5.01.UD1. What am I missing here or is this an Informix bug? Thanks in advance for the help. -- TJ Mills IV *---------------------------------------+--------------------------------------* | mills@SPK.HP.COM | PHYSICAL: T.J. Mills | AT&T: (509) 921-3661 | Hewlett Packard Co | HPDESK: Terence Mills/HP1000 | E 24001 Mission | TELNET: 1-921-3661 | Liberty Lake WA 99019 *---------------------------------------+--------------------------------------* Here is the code that I am trying: EXEC SQL include datetime.h; EXEC SQL include decimal.h; #include <iostream.h> #include <Time.h> #include "/usr/local/mdm/include/Informix.h" main() { EXEC SQL BEGIN DECLARE SECTION; datetime YEAR TO MINUTE dt; datetime YEAR TO MINUTE dt2; EXEC SQL END DECLARE SECTION; char obuff[50], obuff2[50]; Time tj = Time(1988, Time::november,8); // init obuffs strcpy(obuff, ""); strcpy(obuff2, ""); // Init dt dtcurrent(&dt); dtcurrent(&dt2); // Store dt into obuff as ASCII int x = dttofmtasc(&dt, obuff, sizeof(obuff), "%m/%d/%Y %H:%M"); int y = dttoasc(&dt2, obuff2); // Print obuffs result cout << "Result = " << x << " Obuff = " << obuff << endl; cout << "Result = " << y << " Obuff2 = " << obuff2 << endl; // Store obuff into tj tj = make_time(obuff); // Print tj cout << tj << endl; } Here is the output from running the above code: Result = -1228 Obuff = Result = 0 Obuff2 = 1995-03-04 20:50 03/04/95 20:50:36