Re: _oserr = 8, command status = -2 ????(HELP)

Graham R. Leach (leach@cs.concordia.ca) wrote: : Running a report which has always worked before, I come up with an error : which baffles me. : DOS/16M: Unexpected Interrupt=000D at 00F0:013A ^^^^^^^^^^^^^^ This interrupt is caused by a segmentation violation on protected mode 80{34}86 processors. It means a program is trying to write or read memory that does not belong to it. The program is in error. Try to recompile the entire program; if it indeed "has always worked before" and you haven't changed anything, it should still work. Added any new code? Changed operating systems? Executing a report for the first time that uses a branch of the code that was never tested? Good luck. Craig Ludington : code=0000 ss=0328 ds=368 es=0320 : ax=09EA bx=0990 cx=7B3E dx=0320 sp=577A bp=5786 si=15B2 di=1300 : Unable to create menu parse program (_oserr = 8) : The status of the command was: -2. : Further program execution is not possible. : Exiting to system. [ deletia ]